Achim Schneider wrote:
-- That's the one I've been looking for. Remember that
-- return e = [e]
f'''' = concatMap
(\x -> concatMap
(\y -> concatMap
(\_ -> [(x,y)])
(if x*y == 8 then [()] else []))
[2..8])
[1..4]
Morale: Premature term elimination is the root of all misunderstanding.
Haskell wins the wickedness of design contest by using [()] and [] as
truth values.
Maybe you wanted to say: "... by using [()] as True value and [] as
False value" ... which does not seem that wicked (at least to me).
Peter.
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