Peter Verswyvelen <bugf...@gmail.com> wrote:
> Sometimes I do miss the pragmatic C solution:- two function pointers
> that are equal surely represent the same functions (although in C
> nothing is really sure ;)
>
In haskell, they would, but C doesn't give you the same guarantee:
int evil = 0;
int wicked( int i_dare_you ) {
return i_dare_you + (++evil);
}
Clearly, wicked and wicked are the same function, but they surely
aren't indistinguishable, at least if you happen to call them.
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