Hi,
Here is an example:
let l = fun num in
if isIntegral l
then l
else 0
How to do the isIntegral thing?
On Tue, Sep 29, 2009 at 1:58 PM, Magicloud Magiclouds
<magicloud.magiclo...@gmail.com> wrote:
> Hi,
> In other weak-type language, `round i == i` would work. But in
> haskell, what should I do? Thanks.
> --
> 竹密岂妨流水过
> 山高哪阻野云飞
>
--
竹密岂妨流水过
山高哪阻野云飞
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