Mark, Whether a variable is bound or free depends on the scope under consideration. In
(\x. x) (\y. x) the variable x is bound in \x. x, but free in \y. x; hence, it's free in (\x. x) (\y. x) as a whole. However, in \x. (\x. x) (\y. x) it's bound... HTH, Stefan _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
