Hello,

A question recently popped into my mind: does lazy evaluation reduce the
need to "proper" tail-recursion?
I mean, for instance :

fmap f [] = []
fmap f (x:xs) = f x : fmap f xs

Here fmap is not tail-recursive, but thanks to the fact that operator (:) is
lazy, I think that it may still run in constant space/time, am I right?
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe

Reply via email to