Hi,
On 25/04/11 14:20, Ozgur Akgun wrote:
On 25 April 2011 14:11, Angel de Vicente <ang...@iac.es
<mailto:ang...@iac.es>> wrote:
curry :: ((a,b) -> c) -> (a -> b -> c)
is the same as:
curry :: ((a,b) -> c) -> a -> b -> c
thanks, it makes sense now. Somehow I thought that adding the
parenthesis in ...-> (a -> b -> c) was something special and that I
couldn't get rid of them (in the same sense as I cannot get rid of the
parenthesis in the first part and write:
curry :: (a,b) -> c -> a -> b -> c
Thanks,
Ángel
--
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