On Thu, 2012-02-23 at 23:45 +0100, Maxime Henrion wrote: > On Thu, 2012-02-23 at 23:24 +0100, Bas van Dijk wrote: > > * Why do you have the instance: > > > > instance GDeepSeq V1 where grnf _ = () > > > > The only way to construct values of a void type is using ⊥. And I > > would expect that rnf ⊥ = ⊥, not (). I think the best thing is to just > > remove the V1 instance. > > This would have the consequence that any type tagged with a phantom type > (for whatever reason) couldn't be used with deepseq, it would return > bottom.
Sorry, I had myself confused; it wouldn't return bottom, there would just be no way to get an instance for it (the rest of the argument still holds).
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