"riz er" <[EMAIL PROTECTED]> writes: > howMany :: Int -> Int -> Int -> Int > howMany n1 n2 n3 > | (n1 > a) && (n2 > a) && (n3 > a) = 3 > | (n1 > a) && (n2 > a) = 2 > | (n1 > a) && (n3 > a) = 2 > | otherwise = 1 > where a = (n1 + n2 + n3)/3
> i get an error message > "Instance of Fractional Int required for definition of howMany" The problem is that since Haskell knows that n1 et al is an Int, it deduces that a must be an Int (since (>) compares values of the same type). Unfortunately, you're dividing with (/), which provides fractional answers, and not necessarily integers, and certainly not Ints. The easy way out is to consider a different division operator, but you may want to consider the behaviour of your program in the obvious borderline case. -kzm -- If I haven't seen further, it is by standing in the footprints of giants _______________________________________________ Haskell mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell
