Paul D. Smith wrote:
bar should appear in $? in both situations (with or without the ";")
because in both situations, make has decided to rebuild "foo" because
"bar" is "newer".
So, the bug is that "bar" is not present in "$?" when it should be;
basically, $? is only set to prerequisites that are newer than the
target _AND_ that actually exist. In this case, the prerequisite is
considered newer, but doesn't exist.
Ah. I hadn't realized that this was a bug and not a feature. For some
reason I thought that the current behaviour was intended and that the
3.82 behaviour was a change in a feature and not a bug fix.
Now I get it.
John.
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