Yes.
On Mon, Mar 2, 2009 at 3:35 AM, Alain Roger wrote:
> Hi Wil,
>
> so if i understood well, having the following JSON:
>
>> {"records":[{"id":1,"abbreviation":"fre","description":"french"},{"id":2,"abbreviation":"eng","description"
>> :"english"},{"id":3,"abbreviation":"ger","description":"german"},{"id":4,"abbreviation":"svk","description"
>>
>> :"slovak"},{"id":5,"abbreviation":"spa","description":"spanish"},{"id":6,"abbreviation":"usa","description"
>> :"american"},{"id":7,"abbreviation":"ita","description":"italian"},{"id":8,"abbreviation":"por","description"
>>
>> :"portuguese"},{"id":9,"abbreviation":"cze","description":"czech"},{"id":10,"abbreviation":"rus","description"
>> :"russian"},null,null,null]}
>>
>> i should write :
> $.each(data.records, function(i,item){...});
>
> where "data.records" is the name of my JSON result...so records (in my
> JSON).
> am I right ?
>
> A>
>
>
>
