You can't just use .prev() or .next() because the links are within
list items. Instead, you'll need to do something like this:
$('a.active').parent().prev().find('a')
and this:
$('a.active').parent().next().find('a')
--Karl
____________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Dec 27, 2009, at 8:50 PM, Ami wrote:
$('.active').prev()
$('.active').next()
Rate me please if I helped.
On Dec 28, 2:30 am, Toaster <mr.toas...@gmail.com> wrote:
Hello.
Example:
<ul>
<li><a></li>
<li><a class="active"></li>
<li><a></li>
</ul>
How would I be able to get find the next or previous <a> in relation
to the <a class="active">?
I'd appreciate it if anybody could help me out with this. Thanks in
advance.
