https://bugs.kde.org/show_bug.cgi?id=398066
Christian Borntraeger <borntrae...@de.ibm.com> changed:
What |Removed |Added
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CC| |borntrae...@de.ibm.com
--- Comment #1 from Christian Borntraeger <borntrae...@de.ibm.com> ---
looks sane:
normally we compare that dep1 < dep2 (if yes ----> 1, otherwise 0)
the special case is now: dep2 == 0
we then shift right dep1 by 63, (taking the msb of dep1)
then we AND that with 1
-> if msb is set --> 1 otherwise the result is 0.
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