On Sun, Oct 5, 2014 at 2:27 PM, Will Godfrey <[email protected]> wrote:
> > But, what happens if the synth was registered with jack before the > sequencer? > Presumably it is now going to get it's MIDI data *after* it has already > processed that callback. JACK clients are executed in the order required by their interconnections. If client A *sends* data to client B, then client A will always execute before client B. if you're silly enough to create a feedback loop, then the order becomes undefined.
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