Dear All,
Plz see the following code. It gives segmentation fault. ofcourse, it's
right as char *ptr = "abc" sets pointer to the address of the "abc"
string (which may be stored in read-only memory and thus unchangeable).
My doubt : when i run gdb and execute p ptr either after or before
printf, pbc has been displayed. I'm getting segmentation fault only at
the end, it seems, because when i run ./a.out "pbc is not displayed"
but prompted segmentation fault error. why is it so? How does
segmentation fault raises, though pointer-pointing contents has been
changed & even displayed using gdb. Will U plz explain in detail
(internals).
main()
{
char *ptr = "abc";
ptr[0] = 'p';
printf("%s\n",ptr);
}
Thanx in advance.
Krishna Mohan
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