On Thu, 3 Mar 2005 00:38:10 -0600, Hareesh Nagarajan
<[EMAIL PROTECTED]> wrote:
> Hi,
>
> I am aware this is a C-programming mailing list. I just thought I
> might get some useful inputs from this ML.
>
> My problem is that I haven't figured out how I must fsync an output
> stream (in C++) even after reading the contents of this link:
> http://gcc.gnu.org/ml/gcc-help/2004-02/msg00285.html
>
> How must I modify this method (this method doesn't work; it prints the
> error message and exits!) ?
>
> void logRecovery::syncToDisk(fstream& f)
> {
> unix_filebuf_t* buf;
> buf = dynamic_cast<unix_filebuf_t*>(f.rdbuf());
> if (buf == NULL) {
> cerr << "Fatal: Don't know fd of stream" << endl;
> exit(-1);
> }
>
> fsync(buf->fd());
> }
>
> I am using GCC 3.3.4.
>
> Thanks,
>
> Hareesh
> -
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>
I have actually now idea why you are using unix_filebuf_t. Why not
simply call f.flush()? If you need to obtain a reference to the
streambuf object associated with a stream you can call f.readbuf() and
then do a sync, like this:
streambuf *buf;
buf = f.readbuf();
buf->sync();
May be I get you wrong, but hope this helps.
--
Kind Regards
\Steve
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