Thanks very much for your response.
I know that x86 CPU is little endian,but how the printf prints out the
that number which starts from the first lowest byte in mem /stack which is
0x44??
Maybe internally knows that this is a cast???
Lest assume the following example:
#include <stdio.h>
int main(void) {
unsigned int buf = {0x44,0x43,0x42,0x41};
unsigned char *x = (unsigned char*)&buf;
printf("%#x\n", *(int *)x);
return 0;
}
prints out the buf array in reverse order ,little-ednian, and treats it as
a number,
0x41424344
But check out the following example:
endian.txt
-----------
DBCA
.section .data
.filename: .string "endian.txt"
.text
.globl _start
_start:
pushl %ebp
movl %esp,%ebp
movl $5,%eax
movl $.filename,%ebx
movl $0x00,%ecx
int $0x80
movl %eax,%ebx
movl $3,%eax
leal -8(%ebp),%ecx
movl $4,%edx
int $0x80
movl $4,%eax
movl $1,%ebx
movl $0x0a,-4(%ebp)
leal -8(%ebp),%ecx
movl $5,%edx
int $0x80
movl $1,%eax
movl $0,%ebx
int $0x80
#as -o example.o example.s
#ld -o example example.o
#./example
DBCA
We print out the memory from the lowest byte-order.
How can we print out by using the system call 'write' this byte-order and
treat it like a number,as printf does.????????????????????????????????
Thanks in advance.
example.s
----------
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