Em Mon, 31 Aug 2015 14:53:45 +0200
Hans Verkuil <hverk...@xs4all.nl> escreveu:

> On 08/30/2015 05:07 AM, Mauro Carvalho Chehab wrote:
> > Interface links connected to an entity should be removed
> > before being able of removing the entity.
> > 
> > Signed-off-by: Mauro Carvalho Chehab <mche...@osg.samsung.com>
> > 
> > diff --git a/drivers/media/media-device.c b/drivers/media/media-device.c
> > index a91e1ec076a6..638c682b79c4 100644
> > --- a/drivers/media/media-device.c
> > +++ b/drivers/media/media-device.c
> > @@ -618,14 +618,30 @@ void media_device_unregister_entity(struct 
> > media_entity *entity)
> >             return;
> >  
> >     spin_lock(&mdev->lock);
> > +
> > +   /* Remove interface links with this entity on it */
> > +   list_for_each_entry_safe(link, tmp, &mdev->links, graph_obj.list) {
> > +           if (media_type(link->gobj1) == MEDIA_GRAPH_ENTITY
> > +               && link->entity == entity) {
> 
> I don't think you need the == MEDIA_GRAPH_ENTITY check here. That should 
> always be
> true if link->entity == entity.

Yes, I know. Actually, I coded it as just  if (link->entity == entity).
Latter, when reviewing my own patch, I decided to add the extra
check, as it sounded me a little better.

Not sure really what would be the better.

> 
> > +                   media_gobj_remove(&link->graph_obj);
> > +                   kfree(link);
> > +           }
> > +   }
> > +
> > +   /* Remove all data links that belong to this entity */
> >     list_for_each_entry_safe(link, tmp, &entity->links, list) {
> >             media_gobj_remove(&link->graph_obj);
> >             list_del(&link->list);
> >             kfree(link);
> >     }
> > +
> > +   /* Remove all pads that belong to this entity */
> >     for (i = 0; i < entity->num_pads; i++)
> >             media_gobj_remove(&entity->pads[i].graph_obj);
> > +
> > +   /* Remove the entity */
> >     media_gobj_remove(&entity->graph_obj);
> > +
> >     spin_unlock(&mdev->lock);
> >     entity->graph_obj.mdev = NULL;
> >  }
> > 
> 
> Regards,
> 
>       Hans
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