----- Original Message ----- From: "Patrick Bogen" <[EMAIL PROTECTED]>
> On 9/20/06, Bill Landry <[EMAIL PROTECTED]> wrote: >> Is there a simple way to output to a file all lists with each lists >> associated member addresses? I know I can use: >> > snip >> >> for each list, but is there a way to do this in one fell swoop, without >> having to run through each member list individually? > You can do it with some simple shell scripting: > > for i in `bin/list_lists -b`; do bin/list_members $i; done Thanks Patrick, that certainly gives me a listing of all of the member e-mail address for every list, but does not associate them with the particular list they apply to. I was looking for an output like: List-A e-mail-1 e-mail-2 e-mail-3 List-B e-mail-4 e-mail-5 e-mail-6 List-C e-mail-7 e-mail-8 e-mail-9 Bill ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org http://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://www.python.org/cgi-bin/faqw-mm.py Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: http://mail.python.org/mailman/options/mailman-users/archive%40jab.org Security Policy: http://www.python.org/cgi-bin/faqw-mm.py?req=show&file=faq01.027.htp
