On 5/27/22 10:22, John Lake wrote:
Our security department has asked me to canvas all of our lists (4,237!)—and if
a list owner value is not defined they want me to disable the list.
1. Can I combine the list_lists and list_owners commands to output both
(hopefully linked) values as a .csv?
`list_owners -w` will list the owners by list name. If a list has no
owners, only the list name will be output for that list. You could then
process that file to identify the lists with no owners.
2. Is there a script that any of you have leveraged to batch disable lists
without a defined owner?
What do you mean by `disable`?
A withlist script like
```
def no_owner(mlist)
if len mlist.owner == 0:
if not mlist.Locked:
mlist.Lock
print('List %s has no owners, disabling.' % mlist.real_name)
<code here to disable list. I could provide it if I knew what
that meant>
mlist.Save()
mlist.Unlock()
```
saved as no_owner.py in Mailman's bin/ directory and run via
```
bin/withlist -a -r no_owner
```
You could omit the code
```
if not mlist.Locked:
mlist.Lock
<code here to disable list. I could provide it if I knew what
that meant>
mlist.Save()
mlist.Unlock()
```
I.e., just leave the print statement in the `if len mlist.owner == 0:`
clause to just print the names of lists with no owner.
--
Mark Sapiro <m...@msapiro.net> The highway is for gamblers,
San Francisco Bay Area, California better use your sense - B. Dylan
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