On Sun, Oct 25, 2009 at 5:55 PM, David Cleaver <wrai...@morpheus.net> wrote:
> Hello,
>
> I'm having problems printing out values that are larger than 32 bits. My
> usual
> printf using %llu only outputs the lower 32 bits of my 64-bit numbers.
>
> Here's an example program that produces incorrect output.
>
> #include <stdio.h>
>
> typedef unsigned long long u64_t;
>
> int main(int argc, char* argv[])
> {
> u64_t y=6981463658333LL;
> printf("y=%llu\n", y);
%llu is not supported by printf in msvcrt.dll. You can use
%I64u which is the one supported by ms. Or you can use
__mingw_printf(), instead, either explicitly, or indirectly by
defining __USE_MINGW_ANSI_STDIO as 1, for example
by adding -D__USE_MINGW_ANSI_STDIO=1 to your
CFLAGS, which will automaticly replace all printf family
of functions with their __mingw_ counterparts.
> printf("y=%PRIu64\n", y);
Wrong syntax. First you must #include <inttypes.h> for
this. Then, the correct form should be like
printf("y=%" PRIu64 "\n", y);
> printf("y=%qd\n", y);
Same as %ll stuff.
> printf("y=%x\n", y);
> return 0;
> }
>
> Here is the output I get.
> y=2141802333
> y=PRIu64
> y=qd
> y=7fa94f5d
>
> Can anyone see what I'm doing wrong? What is the proper way to output 64-bit
> numbers? I'm using mingw-w64-bin_i686-mingw_20091025.zip for my development
> environment and I've called the compiler like:
> x86_64-w64-mingw32-gcc.exe -o test.exe test.c
>
> Thanks for any help.
>
> -David C.
Use -Wall (or -Wformat) to get warnings about what is
supported and what is not. Hope these help.
--
Ozkan
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