On 11.07.2013 21:08, mugginsoft wrote:
Robert Jordan wrote
Oops, my test actually passes with:
":ToList(System.Collections.Generic.IEnumerable`1
<TSource>
)"
Thanks. I thought I had tried all the combinations - I should have been more
methodical! I wonder why the method name querying functions provide a
different sig?
However (one last however):
Calling the method results in:
* Assertion at method-to-ir.c:6281, condition `!sig->has_type_parameters'
not met
You must "inflate" the generic method upon invocation.
IIRC, there is no function in the embedded API which does this.
What I'm doing is:
1) implement a helper method in C#:
public static IntPtr MakeGenericMethod(MethodInfo method, Type[] parms)
{
// See MSDN's MethodInfo.MakeGenericMethod docs
return method.MakeGenericMethod (parms).MethodHandle.Value;
}
2) mono_runtime_invoke () this method with the following args:
arg 1: the result of mono_method_get_object(the_method). This is
actually a MethodInfo object.
arg 2: a System.Type array containing MonoReflectionTypes* with the
types to be substituted. A MonoReflectionType* is obtained
with mono_type_get_object ().
The helper method returns a MonoMethod* which you can invoke
like a normal non-generic method.
You can do this work solely in C/C++, but using a helper method
would save you some hundred line of convoluted embedded API
invocations. You can save even more code by implementing a couple
of MakeGenericMethod variants that don't need an array argument:
public static IntPtr MakeGenericMethod_1(MethodInfo method, Type parm0)
{
return method.MakeGenericMethod (parm0).MethodHandle.Value;
}
public static IntPtr MakeGenericMethod_2(MethodInfo method, Type parm0,
Type parm1)
{
return method.MakeGenericMethod (parm0, parm1).MethodHandle.Value;
}
public static IntPtr MakeGenericMethod_3(MethodInfo method, Type parm0,
Type parm1, Type parm2)
{
return method.MakeGenericMethod (parm0, parm1,
parm2).MethodHandle.Value;
}
Robert
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