Hi Thomas,
Many many thanks! Danke schön! Yes that was the point: "inmargin"...
Finally the simplest way of achieving my desired result seems to be:
\showframe
\starttext
\setupitemize[stopper=),margin=2.5em]
\startitemize[n,inmargin]
\dorecurse{12}{\item This is question number \recurselevel.}
\stopitemize
\stoptext
where "margin=2.5em" is obtained heuristically (for three digits items
for instance one has to say "margin=3em"). Maybe there is an elegant
method for finding automatically the amount of "margin" depending on
the maximum number of items, but I am not asking that much...
Best regards: OK
On 11/21/05, Thomas A. Schmitz <[EMAIL PROTECTED]> wrote:
> Sorry, I forgot one detail:
>
> On Nov 21, 2005, at 3:59 PM, Otared KAVIAN wrote:
>
> > Hi Thomas and Taco,
> >
> > Thanks for your help, which solves my secondary question... Actually
> > the following works, as suggested by Thomas:
> >
> > \starttext
> > \setupitemize[left=(, right=), width=2em, stopper=,margin=2em]
> > \startitemize[n,inmargin]
> ^^^^^^^^
> > \item one item,
> > \item next item.
> > \item next item.
> > \item next item.
> > \stopitemize
> > \stoptext
> >
> Is that what you're looking for?
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