On 11/21/2012 10:08 AM, Acidrums4 wrote:
Hello there and thanks for finally let me into this mailing list!
So I tried to hack the macro given in the ConTeXt wiki
(http://wiki.contextgarden.net/Page_numbering_in_words) to write pagenumbering
in words in spanish, my native language. Things were great until I had to
reach the 100th page. ConTeXt claims when compiling, but I don't know how to
fix the macro so it can write hundred-numbers.
'Cien' is 100 for spanish. 'Ciento uno' for 101, 'ciento dos' for 102 and so
(You can see a more detailed example in
http://spanish.about.com/cs/forbeginners/a/cardinalnum_beg.htm). So basically
I need to prepend the word 'cien' for each word number from 1 to 99 to write
the one-hundreds, 'doscientos' for the two-hundreds... Here is my dirty hacked
version of the macro (you may save it as 'numstr.tex' for compiling), and a
minimal example as follows:
\input numstr
\defineconversion[numstring][\numstr]
\setupuserpagenumber[numberconversion=numstring]
\starttext
\dorecurse{100}{\recurselevel\page}
\stoptext
I'm such a noob with TeX and I cannot figure out how to do this, and I need
this for this friday!. However, Aditya in the TeX section of StackExchange
(http://tex.stackexchange.com/questions/82722/context-page-numbering-in-words-
for-spanish#comment178155_82722) told me that I could do this witk Lua
(editing the file core-con.lua, as seen in
http://repo.or.cz/w/context.git/blob/HEAD:/tex/context/base/core-con.lua
), 'cause I'm using MkIV for doing this. But I don't know anything about Lua
(seems pretty easy, but I don't know how to test the code Aditya gave me) and
If I knew how to do that, I don't know how to make it work in my document...
All I could do is translate the 'words' array to spanish, but I couldn't do
more... Could you guys give me a hand on this? Thank you so much!
We can add a converter to core-con, but you have to do the checking (and
tuning):
local floor = math.floor
local concat = table.concat
local verbose = { }
local words = {
[1] = "uno",
[2] = "dos",
[3] = "tres",
[4] = "cuatro",
[5] = "cinco",
[6] = "seis",
[7] = "siete",
[8] = "ocho",
[9] = "nueve",
[10] = "diez",
[11] = "once",
[12] = "doce",
[13] = "trece",
[14] = "catorce",
[15] = "quince",
[16] = "dieciséis",
[17] = "diecisiete",
[18] = "dieciocho",
[19] = "diecinueve",
[20] = "veinte",
[21] = "veintiuno",
[22] = "veintidós",
[23] = "veintitrés",
[24] = "veinticuatro",
[25] = "veinticinco",
[26] = "veintiséis",
[27] = "veintisiete",
[28] = "veintiocho",
[29] = "veintinueve",
[30] = "treinta",
[40] = "cuarenta",
[50] = "cincuenta",
[60] = "sesenta",
[70] = "setenta",
[80] = "ochenta",
[90] = "noventa",
[100] = "ciento",
[200] = "doscientos",
[300] = "trescientos",
[400] = "cuatrocientos",
[500] = "quinientos",
[600] = "seiscientos",
[700] = "setecientos",
[800] = "ochocientos",
[900] = "novecientos",
[1000] = "mil",
[1000^2] = "millón",
[1000^3] = "millones",
}
function verbose.spanish(n)
local w = words[n]
if w then
return w
end
local t = { }
local function compose_one(n)
local w = words[n]
if w then
t[#t+1] = w
return
end
local a, b = floor(n/100), n % 100
if a == 10 then
t[#t+1] = words[1]
t[#t+1] = words[1000]
elseif a > 0 then
-- t[#t+1] = words[a]
t[#t+1] = words[100]
end
if words[b] then
t[#t+1] = words[b]
else
a, b = floor(b/10), n % 10
t[#t+1] = words[a*10]
t[#t+1] = "y"
t[#t+1] = words[b]
end
end
local function compose_two(n,m)
if n > (m-1) then
local a, b = floor(n/m), n % m
if a > 0 then
compose_one(a)
end
t[#t+1] = words[m]
n = b
end
return n
end
n = compose_two(n,1000^4)
n = compose_two(n,1000^3)
n = compose_two(n,1000^2)
n = compose_two(n,1000^1)
if n > 0 then
compose_one(n)
end
return #t > 0 and concat(t," ") or tostring(n)
end
verbose.es = verbose.spanish
print(verbose.spanish(31))
print(verbose.spanish(101))
print(verbose.spanish(199))
sort of the english one with some patches (exceptions can be added to
the table if needed)
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