On 8/20/2014 9:38 AM, Xan wrote:
Hi,$\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?
Can you be more explicit? I get the attached.
Thanks, Xan PS: Please CCme ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________
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test.pdf
Description: Adobe PDF document
___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________
