x.min() and x.max() depend on the ordering of the elements: >> x = M.matrix([[ M.nan, 2.0, 1.0]]) >> x.min() nan
>> x = M.matrix([[ 1.0, 2.0, M.nan]]) >> x.min() 1.0 If I were to try the latter in ipython, I'd assume, great, min() ignores NaNs. But then the former would be a bug in my program. Is this related to how sort works? >> x = M.matrix([[ M.nan, 2.0, 1.0]]) >> x.sort() >> x matrix([[ nan, 1. , 2. ]]) >> x = M.matrix([[ 1.0, 2.0, M.nan]]) >> x.sort() >> x matrix([[ 1. , 2. , nan]]) ------------------------------------------------------------------------- Using Tomcat but need to do more? Need to support web services, security? Get stuff done quickly with pre-integrated technology to make your job easier Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642 _______________________________________________ Numpy-discussion mailing list Numpy-discussion@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/numpy-discussion
