Hi again, I apologize, the mistake was entirely my own. Sqrt's do the right thing....
Adam On Sat, Oct 17, 2009 at 12:17 PM, Adam Ginsburg <adam.ginsb...@colorado.edu> wrote: > My code is actually wrong.... but I still have the problem I've > identified that sqrt is leading to precision errors. Sorry about the > earlier mistake. > > Adam > > On Sat, Oct 17, 2009 at 12:08 PM, Adam Ginsburg > <adam.ginsb...@colorado.edu> wrote: >> >> sqrt(float64(1.034324523462345)) >> # 1.0170174646791199 >> f=lambda x: x**2-float64(1.034324523462345)**2 > > should be > f=lambda x: x**2-float64(1.034324523462345) > > so the code I sent was not a legitimate test. > _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
