That was my first thought, but that only warrants me to skip one point in x but not more than one.
>>> x= numpy.arange(10.) >>> delta = 3 >>> print x[(x[1:] - x[:-1]) >= delta] [] instead of the requested [0, 4, 8] Armando Francesc Alted wrote: > A Wednesday 09 June 2010 10:00:50 V. Armando Solé escrigué: > >> Well, this seems to be quite close to what I need >> >> y = numpy.cumsum((x[1:]-x[:-1])/delta).astype(numpy.int) >> i1 = numpy.nonzero(y[1:] > y[:-1]) >> y = numpy.take(x, i1) >> > > Perhaps this is a bit shorter: > > y = x[(x[1:] - x[:-1]) >= delta] > > _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
