Counting the Colors of RGB-Image, nameit im0 with im0.shape = 2500,3500,3 with this code:
tab0 = zeros( (256,256,256) , dtype=int) tt = im0.view() tt.shape = -1,3 for r,g,b in tt: tab0[r,g,b] += 1 Question: Is there a faster way in numpy to get this result? MfG elodw
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