>>> Yes, if BE target shifts out an 32 bit value from address 0, it will
>>> begin with bit0:7, that is byte address 0x03 at targets memory.
>>
>> And host will do the same. When it shifts out 32-bit value , it will
>> put contents of it's address 0x3 to output buffer[0] and send this
>> first.
> I am talking about BE host, off course.
>
> LE host will put contents of it's 0x0 address to buffer[0] and send
> this out first.

Yes, that's the way buf_get_u32 and buf_set_u32 works.

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