for i in `ls`
do
YourScript.shl $i
done
Unless you are also processing your newfile.dat in the script you need
to make unique names for the output files.
Something like:
sed "s/Report by Hosts/$IP| Report by Hosts/" $FN > new_${FN}.dat
so you will get an output file from each input file.
> -----Original Message-----
> From: Johan Muller [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, July 25, 2001 10:26 AM
> To: Multiple recipients of list ORACLE-L
> Subject: UNIX SCRIPT ISSUE - URGENT
>
>
> I need to extract the first 16 bytes of a filename (AIX 4.3)
> which consists of
> an IP address (nnn.nnn.nnn.nnn), and move that to first 16
> positions in the
> file itself, plus adding a pipe (|) sign for a delimiter, and
> save the IP
> address as a file name with a .dat extension, before loading
> the contents into
> a table.
>
> My predecessor concocted the following:
>
> #!/usr/bin/ksh
> FN=$1
> IP=`echo $FN|cut -c1-16`
> sed "s/Report by Hosts/$IP| Report by Hosts/" $FN > newfile.dat
> #-- End of file
>
> which is great for a single file at a time.
>
> Right now I have to perform this surgery on 19 986 files,
> which is in one
> place.
> Using the script above would take me over 20 000 hours.
>
> Any way I can grab the files one at the time based on a ls
> command, and invoke
> the script, and to end up when the last file has been processed.
>
> ALTERNATIVE:
>
> Each file contains the IP address which has to move into the
> first position
> after a string on line 13 which you guessed it: is called 'IP
> Address:'. Is
> their a way vi could be used to achieve the same result?
>
> Any input would be appreciated,
>
>
> Johan Muller
>
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> --
> Please see the official ORACLE-L FAQ: http://www.orafaq.com
> --
> Author: Johan Muller
> INET: [EMAIL PROTECTED]
>
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--
Author: Anderson, Brian
INET: [EMAIL PROTECTED]
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