Possibly to avoid a sort operation (assuming that you might be able to get
away with a NOSORT when doing the full index scan)? It might be deciding
that the benefit of the multi-block reads for the fast full scan are more
than offset by the sort operation that would be needed (and might not be
needed when doing the full index scan).

Regards,

Larry G. Elkins
The Elkins Organization Inc.
[EMAIL PROTECTED]
214.954.1781

> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of
> [EMAIL PROTECTED]
> Sent: Thursday, October 23, 2003 2:39 PM
> To: Multiple recipients of list ORACLE-L
> Subject: Re: index full scan over an index fast full scan in an analytic
> function?
>
>
> i cant attach the 10053 trace. it has proprietary info. There
> isnt much in analytic explain plan either.
>
> does anyone know in general why a full scan would be faster than
> a fast full scan?
> >
> > From: <[EMAIL PROTECTED]>
> > Date: 2003/10/23 Thu PM 03:09:26 EDT
> > To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]>
> > Subject: index full scan over an index fast full scan in an
> analytic function?
> >
> > I have an index on the two columns used in this query. Why
> would the optimizer choose an index full scan over an index fast
> full scan?
> >
> > My question isnt why an index is used, but the type of index scan?
> >
> > select *
> >     from (select col1, col2,
> >           dense_rank()
> >           over (partition by col1
> >                 order by col2 desc)tab
> >           from mytable)
> >    where tab = 1
> >
> > --
> > Please see the official ORACLE-L FAQ: http://www.orafaq.net
> > --
> > Author: <[EMAIL PROTECTED]
> >   INET: [EMAIL PROTECTED]
> >
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-- 
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-- 
Author: Larry Elkins
  INET: [EMAIL PROTECTED]

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