Quoting Mathieu Bouchard <[EMAIL PROTECTED]>:
the helpfile for [lrshift~] is not available through usual means
because someone made a typo in the filename five years ago or something.
Nice! That is exactly the answer I was looking for! Thank you!
I will poke around in the help files to see if I can find the
incorrectly-named help for this object, to see what the related
objects are.
Essential, my question is are there bitwise operators such as [>>]
and [<<] exept working on samples instead of bits. Interestingly,
convolution is basically an audio rate 'and' [&&~], right?
no, convolution is a bunch of sample-wise shifts and [*~] and [+~]
together (as many as there are values in the convolution kernel).
Yes, but conceptually convolution is converting time domain sounds
into frequency domain, storing the values in a sample block, and
multiplying the two blocks together (and normalizing of course). So if
one block has no sound at 300Hz and the other block does, the
resulting block does NOT have sound at 300Hz, right?
So if your block size was four and you had one FFT block that was:
0,1,0,1
And another that was:
0,0,0,1
The convolved "real" sound block (before going to ifft~) would be
0,0,0,1
Right?
Thanks for the object-pointer and the brain-fix!
-thewade
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