On Wed, 27 Dec 2006, Miller Puckette wrote:
Dunno which is should be, but the 'c' language doesn't
allow unary '+' in front of numerical literals... so I
followed that lead.
I don't know which C language you are talking about. Try compiling the
following program with options -ansi -pedantic-errors:
#if + +1
int main (void) {
int foo[+ +1] = { + + + + + + + + + + +1 };
return foo[0];
}
#endif
This demonstrates that unary + works in front of numerical literal, both
in the main language and in the preprocessor. I don't know of a way to
test whether the last + before the 1 is actually considered part of the
literal or not. However, both scanf() and strtod() consider + as part of
a float literal (was there ever a time that they didn't? really?).
_ _ __ ___ _____ ________ _____________ _____________________ ...
| Mathieu Bouchard - tél:+1.514.383.3801 - http://artengine.ca/matju
| Freelance Digital Arts Engineer, Montréal QC Canada
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