[perl #77664] Rakudo parses q\\ as quoting but STD as routine q call

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# New Ticket Created by  Paweł Pabian 
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[14:53] <bbkr> rakudo: q\ \ # parsed as quoting
[14:53] <p6eval> rakudo 5ae715:  ( no output )
[14:53] <bbkr> std: q\ \ # parsed as routine
[14:53] <p6eval> std 32123: OUTPUT«===SORRY!===␤Undeclared 
routine:␤      'q' used at line 1␤Check failed␤FAILED 00:01 114m␤»
[14:53] <bbkr> STD or Rakudo bug?
[14:53] <bbkr> rakudo: (q\ \).WHAT.say
[14:53] <p6eval> rakudo 5ae715: OUTPUT«Str()␤»
[14:55] * moritz_ not sure