At 08:10 PM 05-14-2001 +0100, Graham Barr wrote: >On Mon, May 14, 2001 at 01:56:01PM -0500, Me wrote: > > > Hm, OK. What does this access and using what method ? > > > > > > $foo = '1.2'; > > > @bar[$foo]; > > > > This is an argument against conflating @ and %. > >No it is not. > > > It has nothing to do with using [] instead of {}. > >Yes it does. I was asking if the above is equivalent to > > $bar[$foo] or $bar{$foo} in todays perl. What is the meaning of the following four expressions in Perl6? @bar[$foo]; # A %bar{$foo}; # B @bar{$foo}; # C %bar[$foo]; # D You seem to be advocating A and B, "Me" is advocating A and D. Why is one set better than the other? Later, Buddha
- RE: what I meant about hungarian notation <C. Garrett Goebel>
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation Larry Wall
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation Damian Conway
- Re: what I meant about hungarian notation Michael G Schwern
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation Buddha Buck
- Re: what I meant about hungarian notation Damian Conway
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation John Porter
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation John Porter
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation David L. Nicol
- Re: what I meant about hungarian notation Graham Barr