On Mon, 2002-09-02 at 23:50, Trey Harris wrote:
> No. $0{x} would be set to "grass". $x would stay as 2. $x is in a
> different scope from the hypothetical, so it doesn't get touched.
Ok, it's just taking some time for me to get my head around just what
C</.../> and C<rule{...}> are, but I'm getting there. This makes sense
to me now. Question, is there any way that:
%x = / (moo) {let $cow = $1} /
could magically put the pairs from C<$0> into C<%x>? That would be very
helpful for module authors, I would think.
