The point is that $ is a perfectly valid SQL identifier character and $foo is a perfectly valid identifier. You can always quote any identifier (yes, after case smashing) so you would expect if $foo is a valid identifier then "$foo" would refer to the same identifier.
This case already exists via $1 and "$1". Making '$' a marker for parameters wouldn't introduce it.
-- Andrew Chernow eSilo, LLC every bit counts http://www.esilo.com/ -- Sent via pgsql-hackers mailing list (pgsql-hackers@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-hackers
