Hi,

Saturday, March 5, 2005, 12:38:20 AM, you wrote:
BS> Hello.

BS> How do i print a line return using the echo command, for when i see the
BS> page source,
BS> i get the code line by line and not all in the same line.

BS> using double quotes ( " ), i can put \n at the end and i get the result
BS> i want,
BS> but, using sinle quotes ( ' ), \n doesnt work.

BS> if i use double quotes, in a simple html comand i need to use \"  and i
BS> dont want that.

BS> is any way i could use single quotes, and getting the line feed ??
BS> example:
BS> Double quotes:
BS>     echo "<table border=\"1\" width=\"800px\">\n";

BS> single quotes:
BS>     echo '<table border="1" width="800px">';


BS> cheers

BS> Bruno Santos

BS> -- 
BS> Say no to software patents
BS> www.nosoftwarepatents.com/
BS> --
BS> [EMAIL PROTECTED]
BS> --
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BS> Fax: +351 272 000 257
BS> --
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BS> Fax: +351 272 000 257


you could do:
define('LF',"\n");
echo '<table border="1">'.LF;

-- 
regards,
Tom

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