Errata: in the second to last line I meant: I would like to access the uploaded file from "request.files" at all times, even if not uploaded as multipart/form-data, and use all the convenience methods available for that.
On Thursday, November 2, 2017 at 4:16:24 PM UTC-5, Stefano Cossu wrote: > > Hello, > > I am writing a Flask web server that must accept binary file uploads as > application/x-www-form-urlencoded. E.g. with CURL I would expect to upload > a file as: > > curl -XPOST -H'Content-type: image/jpeg' --data-binary '@my_image.jpg' > http://localhost:5000/upload > > Rather than: > > curl -XPOST --data-binary -F 'file=my_image.jpg' > http://localhost:5000/upload > > The problem is that with the former method the binary is only found in the > "request.stream" and treated as a data stream. I am not sure whether this > is handled entirely in memory, saved to disk, etc. and if a multi-gigabyte > file may blow up my server. > > I would like to use the "request.files" variable to access the uploaded > file from "request.files" and use all the convenience methods available for > that. > > Is there a way I can accomplish that with Flask/Werkzeug? > > Thanks, > Stefano > > -- You received this message because you are subscribed to the Google Groups "pocoo-libs" group. To unsubscribe from this group and stop receiving emails from it, send an email to pocoo-libs+unsubscr...@googlegroups.com. To post to this group, send email to pocoo-libs@googlegroups.com. Visit this group at https://groups.google.com/group/pocoo-libs. For more options, visit https://groups.google.com/d/optout.
