On Tuesday 14 January 2003 11:12 pm, Anthony Heading wrote: > On Tue, Jan 14, 2003 at 04:45:57PM -0600, Frederick Polgardy Jr wrote: > > On Tuesday 14 January 2003 04:41 pm, Anthony Heading wrote: > > > So this appears to be forcing a call to the base class version of the > > > function, which seems rather inappropriate for an rtti() function... > > > > > > Should this not read: > > > res = (QCanvasItem*)sipCpp -> rtti(); > > > > No it doesn't. That's the whole point of a virtual function call. > > rtti() is invoked on the actual object, it's not determined by the ptr > > class. > > Yes.... > > Let me restate, I was being sloppy by including the cast at all. > > Rather than: > res = sipCpp -> QCanvasItem::rtti(); > > should we not have: > > res = sipCpp -> rtti(); > > > The current form is forcibly selecting the base class implementation > of the function.
Yes, so that... class MyItem(QCanvasItem): def rtti(self): QCanvasItem.rtti(self) ...doesn't result recurse ad infinitum. Phil _______________________________________________ PyKDE mailing list [EMAIL PROTECTED] http://mats.gmd.de/mailman/listinfo/pykde