On Wed, Jan 09, 2008 at 11:34:59AM -0800, Brett Cannon wrote:
> On Jan 9, 2008 11:34 AM, Oleg Broytmann <[EMAIL PROTECTED]> wrote:
> > newlist = oldlist.sort(key=lambda v: v.attr_x)
>
> And don't forget about operator.attrgetter().
I don't like it for the task. To use I need to import operator, and
I don't know is it faster or slower than lambda; I suspect it's slower but
I am too lazy to test. Using lambda to get a simple attribute seems much
simpler to me.
Oleg.
--
Oleg Broytmann http://phd.pp.ru/ [EMAIL PROTECTED]
Programmers don't die, they just GOSUB without RETURN.
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