Just van Rossum wrote:
> I don't think that in general you want to fold multiple empty lines into
> one. This would be my prefered regex:
>
> s = re.sub(r"\r\n?", "\n", s)
>
> Catches both DOS and old-style Mac line endings. Alternatively, you can
> use s.splitlines():
>
> s = "\n".join(s.splitlines()) + "\n"
>
> This also makes sure the string ends with a \n, which may or may not be
> a good thing, depending on your application.
s = s.replace("\r", "\n"["\n" in s:])
</F>
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