You can take a memory view of the array directly:
memoryview(array.array("Q", range(1000)))
If your exact use-case is writing to a SharedMemory, then I don't think there
is any simple way to do it without creating some intermediate memory buffer.
(other than using struct.pack_into, or packing the values completely manually)
On 10/10/2021 16:18, Facundo Batista wrote:
> El dom, 10 de oct. de 2021 a la(s) 11:50, Serhiy Storchaka
> (storch...@gmail.com) escribió:
>> 10.10.21 17:19, Facundo Batista пише:
>>> I have a long list of nums (several millions), ended up doing the following:
>>>
>>> struct.pack_into(f'{len(nums)}Q', buf, 0, *nums)
>> Why not use array('Q', nums)?
> You mean `array` from the `array` module? The only way I see using it
> is like the following:
>
>>>> shm = shared_memory.SharedMemory(create=True, size=total_size)
>>>> a = array.array('Q', nums)
>>>> shm.buf[l_offset:r_offset] = a.tobytes()
> But I don't like it because of the `tobytes` call, which will produce
> a huge bytearray only to insert it in the shared memory buffer.
>
> That's why I liked `pack_into`, because it will write directly into
> the memory view.
>
> Or I'm missing something?
>
> Thanks!
>
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