On 2011-05-19, at 11:25 , Łukasz Langa wrote: > Wiadomość napisana przez Stefan Behnel w dniu 2011-05-19, o godz. 10:37: > >>> But why wouldn't "they" expect `b'de' + 1` to work as well in this case? If >>> a 1-byte bytes is equivalent to an integer, why not an arbitrary one as >>> well? >> >> The result of this must obviously be b"de1". > I hope you're joking. At best, the result should be b"de\x01".
Actually, if `b'd'+1` returns `b'e'` an equivalent behavior should be that `b'de'+1` returns `b'df'`. _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
