Hi, Here is one way:
> is.there <- function(mynumber, a, b) mynumber %in% a:b > is.there(4, 1, 10) [1] TRUE > is.there(459124, 103000, 983000) [1] TRUE > is.there(4, 103000, 983000) [1] FALSE HTH, Jorge On Thu, Aug 12, 2010 at 7:10 PM, fishkbob <> wrote: > > So basically I want to do this - > > 4 %in% 1:10 > should return true > > Would there be another way of doing this without having to do the 1:10 > part? > > I am using a very large data set and trying to do > > 459124 %in% 103000:983000 > > multiple times for many values, and it is taking quite a long time > > Also, I would like to vary the x:y part, so I can't even make an object > that > is c(x:y) and do a which(#=c(x:y)) because I would need to change x and y > each time. > -- > View this message in context: > http://r.789695.n4.nabble.com/find-value-between-two-other-numbers-tp2323513p2323513.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
