The following will create a POSIXlt object using the current date:
strptime(sprintf('%06d',breaks),'%H%M%S')
[1] "2010-10-19 07:00:00" "2010-10-19 07:15:00" "2010-10-19 07:30:00"
[4] "2010-10-19 07:45:00" "2010-10-19 08:00:00" "2010-10-19 08:15:00"
[7] "2010-10-19 08:30:00" "2010-10-19 08:45:00" "2010-10-19 09:00:00"
. . .
To get just the hours and minutes, you could use
format(strptime(sprintf('%06d',breaks),'%H%M%S'),'%H:%M')
[1] "07:00" "07:15" "07:30" "07:45" "08:00" "08:15" "08:30" "08:45" "09:00"
[10] "09:15" "09:30" "09:45" "10:00" "10:15" "10:30" "10:45" "11:00" "11:15"
. . .
And I'm still not sure I've answered your question.
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Tue, 19 Oct 2010, Manta wrote:
I do not think that importing the time as character will help me, as I need
to perform several operation with them. Again, maybe I am not able to
express clearly enough. Let's just focus on this series:
breaks
[1] 70000 71500 73000 74500 80000 81500 83000 84500 90000 91500
93000 94500 100000 101500 103000 104500
[17] 110000 111500 113000 114500 120000 121500 123000 124500 130000 131500
133000 134500 140000 141500 143000 144500
[33] 150000 151500 153000 154500 160000 161500 163000 164500 170000 171500
173000 174500 180000 181500 183000 184500
I want a simple function that can convert breaks into a treatable object by
'zoo' as follows:
[1] 07:00 07:15 07:30 ....
..
[33]...
18:00 18:15 18:30 18:45
Is this possible?
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