prop.test() is applicable to a binomial experiment in each of two classes.
Your experiment is binomial only at the subject level. You then have
multiple subjects in each of your groups.
You have a random factor "Subjects" that must be accounted for.
The best way to analyze is a generalized linear mixed model with a
binomial distribution family and a logit or probit link. You will
probably have to investigate overdispersion. If you have a small
number of subjects, and don't care about the among-subject effect,
you can model them as fixed effects and use glm() instead.
Your original question, I believe, related to doing an ANOVA assuming
normality. In order for this to work with this kind of proportion
problem, you generally won't get good results unless the number of
replicates per subject is 12 or more, and the proportions involved
are within 0.15 to 0.85. Otherwise you will have biased confidence
intervals and significance tests.
At 07:51 PM 2/9/2011, array chip wrote:
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Hi Bert,
Thanks for your reply. If I understand correctly, prop.test() is not
suitable to
my situation. The input to prop.test() is 2 numbers for each group
(# of success
and # of trials, for example, groups 1 has 5 success out of 10
trials; group 2
has 3 success out of 7 trials; etc. prop.test() tests whether the
probability of
success is the same across groups.
In my case, each group has several subjects and each subject has 2 numbers (#
success and # trials). So
for group 1:
subject 1: 5 success, 10 trials
subject 2: 3 success, 8 trials
:
:
for group 2:
subject a: 7 success, 9 trials
subject b: 6 success, 7 trials
:
:
I want to test whether the probability of success in group 1 is the
same as in
group 2. It's like comparing 2 groups of samples using t test, what I am
uncertain about is that whether regular t test (or non-pamametric
test) is still
appropriate here when the response variable is actually proportions.
I guess prop.test() can not be used with my dataset, or I may be wrong?
Thanks
John
________________________________
From: Bert Gunter <gunter.ber...@gene.com>
Sent: Wed, February 9, 2011 3:58:05 PM
Subject: Re: [R] comparing proportions
1. Is this a homework problem?
2. ?prop.test
3. If you haven't done so already, get and consult a basic statistical
methods book to help you with questions such as this.
-- Bert
> Hi, I have a dataset that has 2 groups of samples. For each sample, then
> response measured is the number of success (no.success) obatined with the
>number
> of trials (no.trials). So a porportion of success (prpop.success) can be
> computed as no.success/no.trials. Now the objective is to test if
there is a
> statistical significant difference in the proportion of success
between the 2
> groups of samples (say n1=20, n2=30).
>
> I can think of 2 ways to do the test:
>
> 1. regular t test based on the variable prop.success
> 2. Mann-Whitney test based on the variable prop.success
> 2. do a binomial regression as:
> fit<-glm(cbind(no.success,no.trials-no.success) ~ group, data=data,
> family=binomial)
> anova(fit, test='Chisq')
>
> My questions is:
> 1. Is t test appropriate for comparing 2 groups of proportions?
> 2. how about Mann-Whitney non-parametric test?
> 3. Among the 3, which technique is more appropriate?
> 4. any other technique you can suggest?
>
> Thank you,
>
> John
>
>
>
> [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
--
Bert Gunter
Genentech Nonclinical Biostatistics
[[alternative HTML version deleted]]
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