Hi First a handy point : When supplying sample data it is a good idea to use dput(). See ?dput for an explanation. It makes it much easier to see what the data looks like and to work with it. Sample data pasted into a e-mail can get badly mangled. Yours was not bad but still need a bit of cleaning up. I think I'll suggest that this idea goes in the posting guidelines.
Next point: Do you really have two matrices? It looks from the examples you have supplied that you have two data.frames unless all the numerics in the two data sets actually are character values. Try str(data.set) to see what they are. On to more substantive matters. It looks like I misread part of the post. I had assumed that both the 100 X 100 matrix and the 2 X 100 were sorted already and just needed to be joined and sorted. It looks to me like what you want to do is to merge (?merge for info) the two data sets based on the gene names (in merge they should have the same variable name to make life easy ) and then apply the order command to sort by cluster Of the top of my head, and using the example names I used earlier I thin;k you want something like this assuming a common name for the gene name. merge (smat, bmat, by= “gene”) # untested Then apply the order command. I hope I understood the problem this time --- On Mon, 6/27/11, Aparna Sampath <aparna.sampat...@gmail.com> wrote: > From: Aparna Sampath <aparna.sampat...@gmail.com> > Subject: Re: [R] Ordering a matrix based on cluster no > To: r-help@r-project.org > Received: Monday, June 27, 2011, 2:03 AM > Thanks for the help! But when I tried > it, it does not work the same way I > want. :( > after combining the two matrices, they look like this: > > > > V1 > V2 > X > TEL.AML1.C41 > Hyperdip.50.C23 > 1 > TEL.AML1.C41 1 > TEL.AML1.C41 > 1.0000000 0.00000000 > 2 Hyperdip.50.C23 1 > Hyperdip.50.C23 0.0000000 > 1.00000000 > 3 BCR.AB.LC1 > 1 BCR.AB.LC1 > 0.1212121 0.78125000 > 4 Hyperdip.50.C13 1 > Hyperdip.50.C13 0.0000000 > 1.00000000 > 6 TEL.AML1.9 > 1 T.ALL.C5 > 0.0000000 0.03225807 > 7 TEL.AML1.8 > 1 TEL.AML1.9 > 1.0000000 0.00000000 > 8 Hyperdip.50.C7 > 1 TEL.AML1.8 > 1.0000000 0.00000000 > 9 > TEL.AML1.C37 1 Hyperdip.50.C7 > 0.0000000 > 1.00000000 > 11 TEL.AML1.C47 > 1 TEL.AML1.C37 > 1.0000000 0.00000000 > 13 > Hyperdip.50.11 1 MLL.6 > > 0.0000000 0.03225807 > > > when i do : orddata1 <- > df2_a[order(df2_a[,1],decreasing=T),] > > I get the result: > > V1 > V2 > > X > TEL.AML1.C41 > Hyperdip.50.C23 > 22 TEL.AML1.C49 1 > TEL.AML1.2M.1 > 1 > 0.00000000 > 11 TEL.AML1.C47 1 > TEL.AML1.C37 > 1 > 0.00000000 > 1 TEL.AML1.C41 1 > TEL.AML1.C41 > 1 > 0.00000000 > 9 TEL.AML1.C37 1 > Hyperdip.50.C7 > 0 > 1.00000000 > 6 TEL.AML1.9 1 > T.ALL.C5 > 0 > > 0.03225807 > 7 TEL.AML1.8 1 > TEL.AML1.9 > 1 > > 0.00000000 > 16 TEL.AML1.2M.4 1 > Hyperdip.50.11 > 0 1.00000000 > 19 TEL.AML1.2M.1 1 > TEL.AML1.2M.4 > 1 0.00000000 > 15 Hyperdip.50.R2 1 > T.ALL.C10 > 0 > 0.00000000 > 20 Hyperdip.50.C9 1 > BCR.ABL.Hyperdip.R5 0 > 1.00000000 > > > The results are not right! I want it to look for the gene > TEL.AML1.C49 in > the second matrix and group it accordingly. > > Aparna > > -- > View this message in context: > http://r.789695.n4.nabble.com/Ordering-a-matrix-based-on-cluster-no-tp3625956p3627017.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org > mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
