Hi Luciana,
Try this:
yourData[,1] <- sapply(yourData[,1], function(x){
x=as.character(x)
x[which(x=="Toyota2")]<-"Scion"
x
}
)
# Example
set.seed(123)
x=c("Jeep","Nissan", "Toyota1", "Toyota2")
y=rnorm(4)
DATA=data.frame(x,y)
DATA
x y
1 Jeep -0.56047565
2 Nissan -0.23017749
3 Toyota1 1.55870831
4 Toyota2 0.07050839
DATA[,1] <- sapply(DATA[,1], function(x){
x=as.character(x)
x[which(x=="Toyota2")]<-"Scion"
x
}
)
DATA
x y
1 Jeep -0.56047565
2 Nissan -0.23017749
3 Toyota1 1.55870831
4 Scion 0.07050839
HTH,
Jorge
On Tue, Mar 11, 2008 at 2:01 PM, Suran, Luciana @ Torto Wheaton Research <
[EMAIL PROTECTED]> wrote:
> Sorry, another newbie question :-(
>
>
>
>
>
> I loaded a data set with 10 rows and 30 columns. The first column is
> characters for names of car manufacturers:
>
>
>
> Jeep
>
> Nissan
>
> Toyota1
>
> Toyota2
>
> Etc.
>
>
>
> How can I replace "Toyota2" with "Scion"?
>
>
>
> Thanks again
>
>
>
>
>
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> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
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and provide commented, minimal, self-contained, reproducible code.
