Thanks.
So, suppose for one specific year (first year over 10) the percentage of
successes deriving from 100 trials with 38 successes (and 62 failures), its
value would be 38/100=0.38.
I could calculate its confidence intervals this way:
> success<-38
> total<-100
> prop.test(success,total,p=0.5,alternative="two.sided")
1-sample proportions test with continuity
correction
data: success out of total, null probability 0.5
X-squared = 5.29, df = 1, p-value = 0.02145
alternative hypothesis: true p is not equal to 0.5
95 percent confidence interval:
0.2863947 0.4829411
sample estimates:
p
0.38
So it would be var$1=0.38 , CI=0.286-0.483
Is it correct?
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